How does the acceleration of a ball tossed straight upward compare with the acceleration if simply dropped?

Question

Air resistance can be neglected

Answer 1

Assuming both of these things occur on the surface of the Earth at the equator, and you are asking about the acceleration due to gravity immediately after being released, then they both are accelerated downward at a rate of 9.8 m/s/s (or 32 ft/s/s). The only difference is in the initial velocity - zero for the dropped ball, and some upward value for the tossed ball.

Answer 2

speed is the cost that a particle or an merchandise flow in keeping with a undeniable quantity of time and it has a course provided that its a vector quantity whilst acceleration is the substitute in velocity (speed thus) in keeping with a undeniable quantity of time and if a ball is tossed upwards its against gravity so its acceleration is -9.8 m/s^2,and the speed could desire to have a U given and the V could desire to be 0 on the tip bec it reaches at a element and then stops,so its the two you'l get the U r the T i cant extremely understand wht's mandatory in this question

Answer 3

The two situations that you mentioned are totally symmetric. The velocity of the ball at any position on the way up, is equal but opposite to the velocity at the same position on the way down. The acceleration is constant throughout.