solve the equation?

0 ⤊

t^2+1=13/6t

2007-08-25 11:37:16 · 3 answers · asked by luicanna 1 in Science & Mathematics ➔ Mathematics

Reading this as:-
t² + 1 = (13 / 6) t
6t² + 6 = 13t
6t² - 13t + 6 = 0
(3t - 2) (2t - 3) = 0
t = 2 / 3 , t = 3 / 2

2007-08-29 10:47:07 · answer #1 · answered by Como 7 · 0⤊ 0⤋

t^2 + 1 = (13/6)t, Is this what you want?
Multiply each term by 6, and collect all terms in one side,
6t^2-13t+6 = (2t-3)(3t-2) = 0
t = 3/2, 2/3

2007-08-25 19:38:38 · answer #2 · answered by sahsjing 7 · 0⤊ 0⤋

This is really simple, but I'm not doing your homework for you. Let the class do you some good and don't ask online!

2007-08-25 18:42:02 · answer #3 · answered by DeltaKilo3 4 · 0⤊ 0⤋