Alright guys, you do you think would win between these two tag teams in their prime
2007-08-25 10:44:58 · 9 answers · asked by Michael A 4 in Sports ➔ Wrestling
Well, this is a hard one. Blood is thicker than water but when a team has been together and dominating for over two decades...
Point by Point inspection:
Team work:
Edge on Road Warriors (+2)
Finishing move
Wash both teams have a great finisher, doomsday device vs. the steiner bull drop
Individuals:
Steiners have the edge, if it were down to individuals fighting Scott and Rick would have the advantage. (+2)
Titles:
Road Warriors- only team to win a championship in every league and in Japan (+2)
Tag Team Dominance:
The road warriors have put fear in ever team they faced, they didn't care if you were big or fast, they were going to punish you. (+2)
Final Score:
Road Warriors: 7
Steiners: 3
So the winners, at least on paper, would be the Road Warriors....
2007-08-25 11:47:06 · answer #1 · answered by slickkittykattwhopurs 6 · 0⤊ 0⤋
The Steiner Brothers beat the Road Warriors on December 13, 1989 at Starrcade 89.
2007-08-25 11:46:51 · answer #2 · answered by Steve 7 · 0⤊ 0⤋
back in early 90's = Legion of Doom.
after 1995--till now = Steiner Brothers.
2007-08-25 10:56:01 · answer #3 · answered by Anonymous · 0⤊ 0⤋
They've had this match several times....
That said, I always had a preference for the Steiner Bros. (even though I concede LOD is the greatest tag team ever).
2007-08-25 10:59:30 · answer #4 · answered by Anonymous · 0⤊ 0⤋
Road Warriors.
2007-08-25 11:18:58 · answer #5 · answered by Dave 5 · 0⤊ 0⤋
legion of doom in 48:42
2007-08-25 10:53:23 · answer #6 · answered by Anonymous · 0⤊ 0⤋
the steiner brothers
2007-08-25 10:58:44 · answer #7 · answered by "lionheart" Sam Peters 3 · 0⤊ 0⤋
the steiner brothers
2007-08-25 10:53:28 · answer #8 · answered by Ace 7 · 0⤊ 0⤋
Man, what a great question. This would be one of those "dream matches".
L.O.D. would win, but I'd pay money to watch it. It'd be an awesome match.
2007-08-25 10:57:46 · answer #9 · answered by Ronnie H 2 · 0⤊ 0⤋