2007-08-25 10:03:34 · 4 answers · asked by MathDunce 1 in Science & Mathematics ➔ Mathematics
sqrt75/20
=sqrt(25*3)/20
=5sqrt3/20
=sqrt3/4 [after reducing]
2007-08-25 10:13:55 · answer #1 · answered by alpha 7 · 0⤊ 0⤋
Okay look for perfect squares to pull out of 75
Let's work with 75 first... I see 25
So we have sqrt (25 * 3) or 5 sqrt 3
Now we have 5 sqrt3 / 20
We can cancel a 5 to give us
sqrt 3 / 4
note sqrt = square root
2007-08-25 17:11:23 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Given, â(75/20)
=â{(5x5x3)/(2x2x5)}
=â{(5² x 3) / (2² x 5)}
= {(â5² x â3) / (â2² x â5)}
But â5² = 5, & â2² = 2
= (5/2)(â3/â5)
=(5/2) x â(3/5)
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2007-08-25 19:22:45 · answer #3 · answered by Joymash 6 · 0⤊ 0⤋
sqrt(75/20) =
sqrt(15/4) =
sqrt15/sqrt4=
sqrt15/2=
3.872983346/2=
1.936491673.
2007-08-25 17:17:08 · answer #4 · answered by lenpol7 7 · 0⤊ 0⤋