The perimeter of a rectangle is 122 m. The length is 10m more than twice the width. What are the dimensions?
2007-08-25 07:05:20 · 4 answers · asked by Jack M 1 in Science & Mathematics ➔ Mathematics
Let
w = Length
2w + 10 = Length
122 = perimeter
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Perimeter Formula for a rectangle
P = 2L + 2W
122 = 2(2w + 10) + 2w
122 = 4w + 20 + 2w
Collect like terms
122 = 6w + 20
Transpose 20
122 - 20 = 6w + 20 - 20
102 = 6w
Divide both sides of the equation by 6
102 / 6 = 6w / 6
102/6 = w
17 = w
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The width is 17m
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The length = 2w + 20
2(17) + 10
34 + 10
44
The length is 44m
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2007-08-25 07:42:33 · answer #1 · answered by SAMUEL D 7 · 0⤊ 0⤋
P = 2(W + L)
L = 2W + 10
122= 2(W + 2W + 10)
122 = 2(3W + 10)
61 = 3W + 10
51 = 3W
W = 17m
L = 17(2) + 10
L = 44m
44m x 17m
2007-08-25 14:16:58 · answer #2 · answered by 7 · 0⤊ 0⤋
let the width be b
perimeter= 2(l+b)
122=2(2b+10+b) coz lenth is 2b+10
61=3b+10
51=3b
so b=17
l+b=61
so l=61-17=44
so len=44m
width=17m
2007-08-25 14:14:44 · answer #3 · answered by sv1973 2 · 0⤊ 0⤋
x=width
2x+10 =length
2x+2(2x+10)=122
6x+20=122
6x=102
x=17
length=44
2007-08-25 14:12:11 · answer #4 · answered by chasrmck 6 · 0⤊ 0⤋