Write the equation of the line passing through (7,1), (7,-4) and (7, 4)
2007-08-25 06:31:29 · 8 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
x = 7 is required equation.
2007-08-25 08:04:14 · answer #1 · answered by Como 7 · 1⤊ 0⤋
x=7
2007-08-25 13:38:02 · answer #2 · answered by chasrmck 6 · 0⤊ 0⤋
7=x/y
2007-08-25 13:41:31 · answer #3 · answered by thorchristensen 1 · 0⤊ 0⤋
If this is truly a line all you need is two points. Using the point slope formula which is:
y-b = m(x-a) Where m is the slope.
m = (a - y)/(b - x)
Using (7, 1) and (7, 4) you can see right a way that every point is on x is 7 so you would just say
x = 7
2007-08-25 13:38:51 · answer #4 · answered by Xash 3 · 0⤊ 0⤋
since the line passes through x=7 at three instances then it is a straight vertical line and will continue on at x=7 no matter what y is because it is parallel to the y axis and all y values will work for the given x.
So the equation is
x = 7 and y doesn't matter.
2007-08-25 13:47:20 · answer #5 · answered by 037 G 6 · 0⤊ 0⤋
x is always = 7 , so equation is x=7.
Y can be any value you like. The graph is just a vertical line parallel to the y-axis and passing through the point (7,0).
2007-08-25 13:47:13 · answer #6 · answered by ironduke8159 7 · 1⤊ 0⤋
the desired EQ. is x=7.It is satisfied by each of the three points.
2007-08-25 13:45:42 · answer #7 · answered by Anonymous · 0⤊ 0⤋
y = 7x
2007-08-25 13:36:01 · answer #8 · answered by dee 3 · 1⤊ 1⤋