Two six-sided dice are tossed. Find the probability that the sum?

Question

is 5 or less

Answer 1

Since there are 10 combinations (out of a possible 36) that total 5 or less, the probability is 10 out of 36 or about 27.7%.

Answer 2

Assuming that they are *fair* dice,

1+1, 1+2, 1+3, 1+4,
2+1, 2+2, 2+3,
3+1, 3+2,
4+1

Ten good throws out of 36 possible throws.

Probability is 10/36 = 5/18 = about 27.7777778%

Answer 3

10/36 = 5/18

Answer 4

First, evaluate that the risk of having any form on a single die is a million/6. 2d, the only way you will get a 2 is that if the cube the two land on a million. further, the only way you will get a 12 is that if the cube the two land on 6. consequently, the risk that the sum is two or 12 is a million/6 x a million/6 = 2.seventy 8%

Answer 5

event will be tossing dice.
thus,the probability of getting sum to be 5 or less will be
10 i.e,
(1,1) (1,2) (1,3) (1,4) (2,1) 2,2) (2,3) (3,1) (3,2) (4,1) &
total will be
36 i.e, 6*6
P=10/36=5/18