How could you show the presence of both the carbonate and the chloride ions in this mixture....?
as you can see im not very good at chemistry if some one can help...thanks =)
2007-08-25 05:04:37 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
First do a flame test on the solid mixture. Look for the bright yellow color in the flame to confirm Sodium. Also check with a Cobalt filter to rule out any Potassium (the blue glass will mask the yellow Sodium flame so you can see any Potassium).
Next dissolve some of the solid mixture in water. Look to make sure that it all dissolves and does not form any bubbles on its own. Add a few drops of dilute Nitric acid. You should now see bubbles develop in the solution. These are Carbon dioxide from the reaction:
Na2CO3 (aq) + 2 HNO3 (aq) --> CO2 (g) + 2 NaNO3 (aq) + H2O (l)
When all of the CO2 has been released, next add aqueous Silver Nitrate. This will react with the Chloride anions:
AgNO3 (aq) + NaCl (aq) --> AgCl (s) + NaNO3 (aq)
The Silver chloride is a white precipitate.
2007-08-25 19:20:32 · answer #1 · answered by Richard 7 · 10⤊ 0⤋
Add dilute nitric acid. There will be a lot of fizzing, and you can test for CO2. That will mean you had a carbonate. When the fizzing has stopped (excess acid) add silver nitrate solution. You will get a white precipitate of silver chloride, showing you had the chloride ion.
2007-08-25 06:12:50 · answer #2 · answered by Gervald F 7 · 0⤊ 0⤋
They do not need the identical cleansing potential- regularly in view that the polarity of the substance is converted. With the additional carbonate ion in sodium bicarbonate, the polarity ( its potential to dissolve) is converted in view that of extraordinary electronegativity with the additional ion. THerefore, you'll be able to say that their first-class of labor don't seem to be the identical. However, you're proper in pronouncing that they each paintings as cleansing dealers. Besides, the noticeable change is within the PH phases. Sodium carbonate is round 10, even as sodium bicarbonate has a ph of round 6.three. Therefore, they don't seem to be even the identical substance! ONe is an acid at the same time the opposite is a base. Hope this is helping. Just verify the next 2 web sites
2016-09-05 13:38:04 · answer #3 · answered by Anonymous · 0⤊ 0⤋
add some silver nitrate to an acidic solution. if you get a white precipitate of silver chloride there are chloride ions.when an acid is added to carbonate co2 is produced. you can identify co2 with the use of calcium hydroxide.
2007-08-25 06:26:52 · answer #4 · answered by Jewl 2 · 0⤊ 0⤋