A gaseous mixture containing 4.15 mol hydrogen gas and 7.13 mol oxygen gas reacts to form steam?

Question

what would the balanced equation be??
i got 7O2 + 14 H2 yeilds 14 H2O
but could i use O2 + 2 H2 yeilds 2 H2O?
the next question is what is the limiting reactant

Answer 1

yes u can use the second equation too
actually the second one is the one we use
O:H=1:2
so that means if u have 1 mol of Oxygen u need 2 mols of Hydrogen
But in here the number of Hydrogen mols is less than the amount of O2 mols
so Hydregen limits the reaction from reacting anymore
So the limiting reactant is Hydrogen


If u use the equation u mentioned before O:H is the same
7:14=1:2
but we only use the most simplest fraction(1 :2 ) when equaliing an equation

sorry about the spelling
English is not my first language

Good Luck !
:)

Answer 2

Assuming nothing more complex is going on, the balanced equation would be 4 H2 + 7 O2 -> 4 H20 + 3 O2. The limiting reactant would be hydrogen.

Answer 3

It is O2+2 H2-->2 H2O

The limiting reactant is hydrogen because there is not enough hydrogen to react with all of the oxygen. Going one step further, the amount of steam:

4.15mol H2 x (2mol H20/2mol H2)

The answer is that 4.15 mol of H2O is left over, using Dimensional Analysis.

Answer 4

because of the fact the chemical reaction motives steam the temperature could be someplace approximately 211 stages for this to happen. And if this occurs at 212 stages does it advise that the two gases could combination on the temperature above a given factor? I element the fee element has no longer something to do with this reaction yet temperature and altitude do.

Answer 5

2H2 + O2 ----> 2H2O is the equation however much or however little you have.

7.13 moles O2 requires 14.26 moles H2. Have you got that much? No, so H2 is your limiting reagent.