3x - y - 2z = 11
x + y - 2z = 5--------ADD
4x - 4z = 16
x - z = 4
x - 2y + 3z = 12
2x + 2y - 4z = 10----ADD
3x - z = 22
x - z = 4
- 3x + z = - 22----ADD
- 2x = - 18
x = 9
z = 5
x + y - 2z = 5
9 + y - 10 = 5
y = 6
x = 9 , y = 6 , z = 5
2007-08-24 19:52:07
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answer #1
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answered by Como 7
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Simultaneous linear equations: If they are independent, you solve by substitution.
For example, the last equation becomes:
x = 2z - y- 5.
Plug this into the equation above it:
x - 2y + 3z = 12 becomes 2z - y - 5 - 2y + 3z = 12
Rearrange:
5z - 3y = 17
Now, this means that 5z = 3y + 17
So, you plug this and the previous equation into the third (as yet unused) equation and you are left with an expression that is in z only.
Once you have z, compute y
Once you have y, compute x
2007-08-25 02:50:24
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answer #2
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answered by Anonymous
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1st equation (finding x):
3x - y - 2z = 11
3x = 11 + y + 2z
x = (11 + y + 2z) / 3
x = 11/3 + 1/3y + 2/3z
2nd equation (finding y, substitute x):
11/3 + 1/3y + 2/3z - 2y + 3z = 12
- 1 2/3y + 3 2/3z = 12 - 11/3
- 1 2/3y = 25/3 - 3 2/3z
y = - 5 + 11/5z
1st equation (substitute y):
x = 11/3 + 1/3(- 5 + 11/5z) + 2/3z
x = 11/3 - 5/3 + 11/15z + 2/3z
x = 2 + 7/5z
3rd equation (finding z, substitute x and y):
(2 + 7/5z) + (- 5 + 11/5z) - 2z = 5
2 + 7/5z - 5 + 11/5z - 2z = 5
8/5z = 8
z = 5
1st equation (finding x, substitute z)
x =2 + 7/5(5)
x = 2 + 7
x = 9
2nd equation (substitute z):
y = - 5 + 11/5(5)
y = - 5 + 11
y = 6
Answer: x = 9; y = 6; z = 5
Proof:
1st equation:
3(9) - 6 - 2(5) = 11
27 - 6 - 10 = 11
2007-08-25 04:34:45
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answer #3
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answered by Jun Agruda 7
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get rid of y in the first and third equation
3x - y - 2z = 11
x + y - 2z = 5
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4x - 4z = 16
get rid of y in the first and second equation
-2(3x - y - 2z = 11)
x – 2y + 3z = 12
-6x + 2y + 4z = -22
x – 2y + 3z = 12
---------------
-5x + 7z = -10
4x - 4z = 16
-5x + 7z = -10
5(4x - 4z = 16)
4(-5x + 7z = -10)
20x - 20z = 80
-20x + 28z = -40
-----------------------
8z = 40
z = 5
-5x + 7(5) = -10
-5x + 35 = -10
-5x = -45
x = 9
9 + y - 2(5) = 5
y = 6
2007-08-25 03:05:00
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answer #4
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answered by 7
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Actually wat u want...................
The answer for the question or the method to solve.......
if answer,,,it is
x=9
y=6
z=5
2007-08-25 02:51:16
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answer #5
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answered by vanitha 1
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