2007-08-24 15:38:52 · 9 answers · asked by Ciavana 3 in Science & Mathematics ➔ Mathematics
f(x)=3x+10
[f(10+h)-f(10)]/h
whenever you see the x you have to replace by 10+h if you want to figure f(10+h), and replace by 10 if you want to find f(10)
but be carefully with - f(10) that means you subtract the whole thing thing you figure out f(10), need to have a parentheses
therefore f(10+h)= 3(10+h)+10
f(10)= 3(10) +10
=[3(10+h)+10-(3(10)+10)]/h
=(30+3h +10 -30 -10)/h
= 3h/h = 3
2007-08-24 15:47:19 · answer #1 · answered by Helper 6 · 2⤊ 2⤋
F(x)=3x+10
=[3(10+h)+10-[3(10)+10]]
=(30+3h+10-(30+10))/h
=(40+3h-40)/h
=(3h)/h
=3
2007-08-24 23:17:58 · answer #2 · answered by Anonymous · 0⤊ 1⤋
This is the defintion of the derivative
f'(x)=3
[f(10+h) - f(10)]/h
=[3*(h+10) +10 - ( 3*10 +10)]/h
=[3h+40-40]/h
=3
2007-08-24 22:50:15 · answer #3 · answered by Anonymous · 2⤊ 0⤋
{3(10+h) - 10 - 3(10) +10}/h
{30 + 3h - 10 - 30 +10}/h
notice how 30 and -30, 10 and -10 cancel out you're left with
3h/h = 3
This is the derivative
2007-08-24 22:48:14 · answer #4 · answered by Leo 3 · 1⤊ 0⤋
subtitude (10+h) in the equation
so, [3(10+h)+10-(3(10)+10)]/h
=[ 30+3h+10-40]/h
=3h/h
=3
2007-08-24 22:49:06 · answer #5 · answered by iman 2 · 1⤊ 0⤋
just take 10+h and replace it for x and then take 10 and replace x with it. The answer would be:
[f(10+h) - f(10)]/h = {[3(10 + h) + 10] - (3*10 + 10)}/h
2007-08-24 22:47:24 · answer #6 · answered by Xash 3 · 0⤊ 1⤋
((3(10 + h) + 10)- ( 3(10)+10))/h
(30+3h+10-30-10)/h
You will know you did it right when all the terms cancel
30 and 10 are subtracted by themselves to get 3h/h
Divide by h to get 3
2007-08-25 00:01:50 · answer #7 · answered by james w 5 · 0⤊ 1⤋
[ 3 (10 + h ) + 10 - (40) ] / h
[ 30 + 3h + 10 - 40 ] / h
3h / h
3
2007-08-25 04:34:03 · answer #8 · answered by Como 7 · 2⤊ 1⤋
f(x)=3x+10
[f(10+h)-f(10)]/h
=[3(10+h)+10-3(10)+10]/h
=(20+h)/h
=20/h+1
2007-08-24 22:44:15 · answer #9 · answered by Matthew T 2 · 0⤊ 3⤋