The present population, P, in thousands, of a town is related to the initial population of the town at time t = 0 by the formula
P = 125(3)(0.05t)
where t is measured in years. The town was populated in 1880.
What was the population of the town in 1880?
2007-08-24 14:28:18 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
the (0.05) is used as a power...
2007-08-24 14:55:23 · update #1
t = 0 in 1880
P = 125 x 3^0
P = 125 x 1
P = 125
Population was 125,000 in 1880
2007-08-24 20:02:45 · answer #1 · answered by Como 7 · 1⤊ 0⤋
You don't specify which year was t=0.
Assuming t=0 was year 0, then the year 1880 is t=1880 so simply put this value in your equation:
P = 125(3)(0.05*1880)=35250
OK so I'm editing this now to take account of the power:
P = 125*3^(0.05t) = 125 * 3^(0.05*1880) = 8.8 * 10^46 which is obviously pretty huge, so I'm guessing the year of t=0 was not the year 0.
2007-08-24 14:48:20 · answer #2 · answered by Anonymous · 0⤊ 0⤋
P = 125(3)(0.05^t)
when t = 1880,
P = 125[3^(0.05*1880)]
P = 8.837 x 10^46 (to 4 significant figures)
2007-08-24 15:28:49 · answer #3 · answered by Anonymous · 0⤊ 0⤋
t = 0 in 1880
P = 125 x 3^0
P = 125 x 1
P = 125
Since the population is in thousands, then:
Population was 125,000 in 1880
2007-08-25 01:53:24 · answer #4 · answered by Sparks 6 · 0⤊ 1⤋