2007-08-24 12:23:09 · 8 answers · asked by m-o-o-n 3 in Science & Mathematics ➔ Mathematics
Hey there!
Here's the answer.
-2x^2+x+15 --> Write the problem.
-(2x^2-x-15) --> Factor out -1.
-(2x^2-6x+5x-15) --> Rewrite -x as -6x+5x.
-(2x(x-3)+5(x-3)) --> Factor out 2x in 2x^2-6x and factor out 5 in 5x-15.
-(2x+5)(x-3) Factor out 2x+5.
So the answer is -(2x+5)(x-3).
Hope it helps!
2007-08-24 12:35:57 · answer #1 · answered by ? 6 · 1⤊ 0⤋
-2x^2 + x + 15
-2x^2 + 6x - 5x + 15
-2x(x - 3) -5(x - 3)
(-2x - 5)(x - 3)
-(2x + 5)(x - 3)
To factor a quadratic equation(ax^2 + bx + c), split 'b' into two numbers whose product equals the product of 'a' and 'c'.
2007-08-24 19:30:51 · answer #2 · answered by Anonymous · 2⤊ 0⤋
factor out the leading negative -- math people don't like to start polynomials with negatives.
-(2x^2 - x - 15)
-(2x+5)(x-3)
2007-08-24 19:37:00 · answer #3 · answered by Sage B 4 · 1⤊ 0⤋
look for two numbers that multiply to -30 and add to 1
the two numbers are -5 and 6
-2x^2 - 5x + 6x + 15
factor by groups
(-2x^2 - 5x) + (6x + 15)
-x(2x + 5) + 3(2x + 5)
(2x + 5) (-x + 3)
- (2x + 5) (x - 3)
2007-08-24 19:33:02 · answer #4 · answered by 7 · 1⤊ 0⤋
-2x^2+x+15
these are the factiors:
6 * -5 = -30; this is a * c
6 + -5 = 1; this is b
so: -2x^2+x+15
-2x^2+6x-5x+15
(-2x^2+6x)(-5x+15)
-2x(x-3)-5(x-3)
(-2x-5)(x-3)
-(2x+5)(x-3)
2007-08-24 19:49:44 · answer #5 · answered by Anonymous · 1⤊ 0⤋
-2x² + x + 15 =
-(2x² - x - 15) =
-(2x + 5)(x - 3)
2007-08-24 19:32:27 · answer #6 · answered by Philo 7 · 1⤊ 0⤋
(-2x-5)(x-3)
2007-08-24 19:33:22 · answer #7 · answered by GTB 7 · 1⤊ 0⤋
use the quadratiic!
2007-08-24 19:30:17 · answer #8 · answered by roguetrader12002 4 · 0⤊ 2⤋