make the numbers x & y.
x-y = 4
x^2 + y^2 = 170
now solve this equation knowing that
x = 4+y
we get:
(4+y)^2 + y^2 = 170
16 + 8y + 2y^2 = 170
y^2 + 4y - 77 = 0
(y+11)(y-7) = 0
y can be 7 or -11 in which case x= 11 or -7
but only the first case holds to satisfy the requirement that both numbers be positive.
2007-08-24 08:41:30
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answer #1
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answered by 037 G 6
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Two equations:
x - y = 4
x^2 + y^2 = 170
so, x = y+4
substitute y +4 into the second equation for x and get:
(y + 4)^2 + y^2 = 170
y^2 + 8y + 16 + y^2 = 170
2y^2 + 8y + 16 = 170
divide by 2
y^2 + 4y + 8 = 85
subtract 85
y^2 + 4y - 77 = 0
factor
(y - 7)(y + 11) = 0
so. y = 7 or -11
no negative numbers per the question's parameters, so
y = 7
x - 7 = 4
so the answer is : 7 and 11
check the answer
7^2 + 11^2 = 170
49 + 121 = 170
170 = 170.
2007-08-24 08:49:43
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answer #2
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answered by Spicemon 2
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A little algebra will suffice. Let the numbers be x and y. We are given x = y-4; x^2 + y^2 = 170. Then, (y-4)^2 + y^2 = 170; 2y^2 -8y + 16 = 170; y^2 -4y -77 = 0; and the numbers are 7 and 11.
2007-08-24 08:45:11
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answer #3
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answered by Anonymous
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let x and y be the two numbers
x - y = 4
x^2 + y^2 = 170
x = y + 4
(y + 4)^2 + y^2 = 170
y^2 + 8y + 16 + y^2 = 170
2y^2 + 8y - 154 = 0
2 (y + 4y - 77) = 0
2 (y + 11) (y - 7) = 0
y = -11 or 7
since the question ask for a positive number, take 7
x - y = 4
x - 7 = 4
x = 11
so 11 and 7
2007-08-24 08:45:20
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answer #4
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answered by 7
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x-y =4
x^2 + y^2 = 170
Substituting (4+y) for x in the second equation yields
y^2 + 4 y - 77 =0
which has a positive root at 7.
y=7
x=11
and indeed, 49+121 = 170
2007-08-24 08:45:16
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answer #5
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answered by Vincent G 7
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To answer your first question: not very smart.
Second question:
x - y = 4
x^2 + y^2 = 170
x - y = 4
Add y to both sides:
x = 4 + y
Substitute x=4+y:
(4 + y)^2 + y^2 = 170
F.o.i.l. out first term:
16 + 8y + y^2 + y^2 = 170
Subtract 170 from both sides:
-154 +8y + 2y^2 = 0
Rearrange terms and divide both sides by 2:
y^2 + 4y - 77 = 0
Factor:
(y + 11)(y - 7) = 0
y = -11 (this is negative so it doesn't work)
or
y = 7
So y = 7
x - 7 = 4
x = 11
The two numbers are 7 and 11.
2007-08-24 08:41:59
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answer #6
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answered by whitesox09 7
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ok this could be answered in many forms...
let the number be x and the other be x + 4... difference can be seen in any form you want to see... the difference between x+4 and x is 4...
x^2 + (x+4) ^ 2 = 170... rest is simple algebra...
2007-08-24 09:01:26
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answer #7
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answered by Clinically Insane 3
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What you said was :
x² + (x + 4)² = 170.
So 2x² + 8x - 154 = 0.
Or 1x² + 4x - 77 = 0
Factor or use the quadratic formula.
Go from there.
2007-08-24 10:59:55
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answer #8
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answered by Mark 6
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7 and 11
2007-08-24 08:42:01
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answer #9
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answered by mitchellinho 4
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3 and 7
2007-08-24 08:49:18
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answer #10
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answered by Anonymous
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