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The difference of two positive numbers is four. The sum of their squares is 170. What are the numbers? Explain.

Lets see who can answer that one!

2007-08-24 08:38:33 · 24 answers · asked by Anonymous in Science & Mathematics Mathematics

24 answers

make the numbers x & y.

x-y = 4
x^2 + y^2 = 170
now solve this equation knowing that
x = 4+y
we get:
(4+y)^2 + y^2 = 170

16 + 8y + 2y^2 = 170
y^2 + 4y - 77 = 0
(y+11)(y-7) = 0

y can be 7 or -11 in which case x= 11 or -7

but only the first case holds to satisfy the requirement that both numbers be positive.

2007-08-24 08:41:30 · answer #1 · answered by 037 G 6 · 1 3

Two equations:

x - y = 4

x^2 + y^2 = 170

so, x = y+4

substitute y +4 into the second equation for x and get:

(y + 4)^2 + y^2 = 170

y^2 + 8y + 16 + y^2 = 170

2y^2 + 8y + 16 = 170

divide by 2

y^2 + 4y + 8 = 85

subtract 85

y^2 + 4y - 77 = 0

factor

(y - 7)(y + 11) = 0

so. y = 7 or -11

no negative numbers per the question's parameters, so

y = 7

x - 7 = 4

so the answer is : 7 and 11

check the answer

7^2 + 11^2 = 170

49 + 121 = 170

170 = 170.

2007-08-24 08:49:43 · answer #2 · answered by Spicemon 2 · 1 1

A little algebra will suffice. Let the numbers be x and y. We are given x = y-4; x^2 + y^2 = 170. Then, (y-4)^2 + y^2 = 170; 2y^2 -8y + 16 = 170; y^2 -4y -77 = 0; and the numbers are 7 and 11.

2007-08-24 08:45:11 · answer #3 · answered by Anonymous · 1 1

let x and y be the two numbers
x - y = 4
x^2 + y^2 = 170

x = y + 4

(y + 4)^2 + y^2 = 170
y^2 + 8y + 16 + y^2 = 170
2y^2 + 8y - 154 = 0
2 (y + 4y - 77) = 0
2 (y + 11) (y - 7) = 0
y = -11 or 7

since the question ask for a positive number, take 7

x - y = 4
x - 7 = 4
x = 11

so 11 and 7

2007-08-24 08:45:20 · answer #4 · answered by      7 · 1 1

x-y =4

x^2 + y^2 = 170

Substituting (4+y) for x in the second equation yields

y^2 + 4 y - 77 =0

which has a positive root at 7.

y=7
x=11

and indeed, 49+121 = 170

2007-08-24 08:45:16 · answer #5 · answered by Vincent G 7 · 1 0

To answer your first question: not very smart.

Second question:
x - y = 4
x^2 + y^2 = 170

x - y = 4
Add y to both sides:
x = 4 + y

Substitute x=4+y:
(4 + y)^2 + y^2 = 170
F.o.i.l. out first term:
16 + 8y + y^2 + y^2 = 170
Subtract 170 from both sides:
-154 +8y + 2y^2 = 0
Rearrange terms and divide both sides by 2:
y^2 + 4y - 77 = 0
Factor:
(y + 11)(y - 7) = 0
y = -11 (this is negative so it doesn't work)
or
y = 7

So y = 7

x - 7 = 4
x = 11

The two numbers are 7 and 11.

2007-08-24 08:41:59 · answer #6 · answered by whitesox09 7 · 2 1

ok this could be answered in many forms...

let the number be x and the other be x + 4... difference can be seen in any form you want to see... the difference between x+4 and x is 4...

x^2 + (x+4) ^ 2 = 170... rest is simple algebra...

2007-08-24 09:01:26 · answer #7 · answered by Clinically Insane 3 · 0 0

What you said was :

x² + (x + 4)² = 170.

So 2x² + 8x - 154 = 0.

Or 1x² + 4x - 77 = 0

Factor or use the quadratic formula.

Go from there.

2007-08-24 10:59:55 · answer #8 · answered by Mark 6 · 0 0

7 and 11

2007-08-24 08:42:01 · answer #9 · answered by mitchellinho 4 · 0 3

3 and 7

2007-08-24 08:49:18 · answer #10 · answered by Anonymous · 0 4

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