Find the vertex of the parabola.
x^2 - 2x + 44y + 353 = 0
2007-08-24 08:25:58 · 9 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
x^2 - 2x + 44y + 353 = 0
x^2 -2x +1 +44y +353 = 1
(x-1)^2 +44y = -352
44y = -(x-1)^2 -352
y = -1/44(x-1)^2 -8
y+8 = -1/44(x-1)^2
So vertex is at (1,-8)
2007-08-24 08:43:00 · answer #1 · answered by ironduke8159 7 · 0⤊ 0⤋
Im sorry but I can only help you have way I havent done math all summer.
X2-2x+44y+353=0
44 44 <- subtract
X2-2x +309=0
2x 2x=0 <-Divide
X2 154.5=0
Im sorry but thats as far as I can go
2007-08-24 15:35:54 · answer #2 · answered by ~*[AnD]*~ 4 lyfe 2 · 0⤊ 0⤋
x^2-2x+1 = -44y-352
-(x-1)^2= 44(y+8)
V(1, -8)
Saludos
2007-08-24 15:33:29 · answer #3 · answered by lou h 7 · 1⤊ 0⤋
x²-2x+1+44y+352+0
8-(x-1)²/44 =y
vertex is (1,8)
2007-08-24 15:33:28 · answer #4 · answered by chasrmck 6 · 0⤊ 0⤋
Solve for y, and then plug it into a graphing calculator. On most of them, there is a function where you select endpoints and the vertex is found between them.
2007-08-24 15:32:09 · answer #5 · answered by Alecto 5 · 0⤊ 0⤋
haha
its
(1,-8)
use a graphing calc
or u cod start out by solving for y
and then using the x=-b+or- the root of b^2-4ac
all over 2a
:-)
2007-08-24 15:36:26 · answer #6 · answered by quizzie 1 · 0⤊ 0⤋
Do your own homework. How will you learn if all you do is ask people?
2007-08-24 15:32:05 · answer #7 · answered by SL65 AMG 4 · 0⤊ 0⤋
do your own homework. or wait till i have to go back to school and do mine.
2007-08-24 15:31:04 · answer #8 · answered by Anonymous · 0⤊ 0⤋
wow looks hard!
2007-08-24 15:30:08 · answer #9 · answered by Emmy =) 3 · 0⤊ 0⤋