This site uses calculus to show that the frog will.
http://www.fortunecity.com/lavender/eraserhead/708/math.htm
"The first is the famous "frog and the wall" problem. Iplace a frog one foot from a wall and tell him to jump half way tothe wall, then jump half way to the wall again, then jump half wayto the wall again, and keep going. Does the frog ever reach thewall? Of course he does."
You can find the complete explanation in the section for problem 11.
2007-08-24 08:21:38
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answer #1
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answered by Michelle at AskAway Wisconsin 3
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Your question can be translated to can we divide a number by 2 a finite number of times and reach 0.
The answer is no.
However,
Lets assume that there is a finite length of of space that is atomic (Plank's constant.) Eventually you will reach a point where you have jumped to the atomic unit of space just before the end. Since this is an atomic unit of space, you cannot divide it further. If you choose to jump, you either go all the way or you don't move at all. If your definition of jump is to round up, you will indeed reach the destination. If your definition of jump is to round down or truncate, you will never reach the destination.
2007-08-24 15:19:37
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answer #2
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answered by Joe 4
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This is a rewording of Zeno's paradox.
http://en.wikipedia.org/wiki/Zeno's_paradox#Achilles_and_the_tortoise
The short answer is no. Of course we're going on the assumptiont hat the frog can always jump half of the remaining distance. At some point, probably less than 100 jumps in fact, we'd be asking the frog to go a distance that's smaller than an atom's nucleus.
2007-08-24 15:14:43
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answer #3
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answered by Anonymous
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No, I don't believe so. You're asking if the frog always jumps half the distance he jumped before, will he eventually reach the wall?
The distance is 1. the frog jumps half of that, so he's travelled 0.5. If he jumps half of 0.5, he'll jump 0.25 and be at 0.75.
And so on:
0.75 + (0.25 / 2) = 0.75 + 0.125 = 0.875
0.875 + (0.125 / 2) = 0.875 + 0.0625 = 0. 9375
0.9375 + (0.0625 / 2) = 0.9375 + 0.03125 = 0.96875
0.96875 + (0.03125 / 2) = 0.96875 + 0.015625 = 0.984375
0.984375 + (0.015625/2) = 0.984375 + 0.0078125 = 0.9921875
0.9921875 + (0.0078125/2) = 0.9921875 + 0.00390625 = 0.99609375
0.99609375 + (0.00390625/2) = 0.99609375 + 0.001953125 = 0.998046875
You'll find you can come really close to 1, but you won't ever reach one. To reach one, you'd need another 0.5, and you won't ever get it if you keep adding half.
2007-08-24 15:47:26
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answer #4
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answered by Anonymous
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No. Using that scenario, the frog will never reach the wall.
It will, however, get _extremely_ close to the wall.
2007-08-24 15:09:04
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answer #5
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answered by credo quia est absurdum 7
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no, if it keeps jumping halfway to the wall it wont jump all the way to the wall.
2007-08-24 15:08:51
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answer #6
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answered by Crimson Crow 3
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Yes
It will take 34 jumps
the 33rd jump will be 0.000000001
34th jump reads 6.98491931-10
not unless I am reading it wrong.
2007-08-24 16:19:27
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answer #7
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answered by skittles2 2
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This is the Zenon paradox.
It would never reach the wall
2007-08-24 15:10:34
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answer #8
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answered by santmann2002 7
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According to the Paradox of Zeno the answer is NO.
2007-08-24 15:09:03
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answer #9
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answered by Anonymous
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Technically, no, because you can always take half of the distance. (Eventually, he'd be jumping infinitely small amounts.)
2007-08-24 15:11:10
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answer #10
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answered by Mathematica 7
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