Write the standard equation, the center, and the radius for the circle:
x^2 + y^2 + 10x + 12y + 60 = 0
2007-08-24 07:46:25 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Standard form: (x - h)^2 + (y - k)^2 = r^2
where (h, k) is center, r = radius
x^2 + y^2 + 10x + 12y + 60 = 0
(x^2 + 10x) + (y^2 + 12y) = -60
(x^2 + 10x + 25) + (y^2 + 12y + 36) = -60 + 25 + 36
(x + 5)^2 + (y + 6)^2 = 1
(-5, -6) and 1
2007-08-24 08:00:41 · answer #1 · answered by Mathematica 7 · 0⤊ 0⤋
x^2 + y^2 + 10x + 12y + 60 = 0
x^2 + 10x + 25 + y^2 + 12y + 36 = 25 + 36 - 60
(x + 5)^2 + (y + 6)^2 = 1
Center at (- 5, - 6)
Radius = 1
2007-08-24 15:01:59 · answer #2 · answered by Helmut 7 · 0⤊ 0⤋
x²+10x+25 + y²+12y+36 =1
(x+5)² + (y+6)² = 1²
center is (-5,-6) radius is 1
2007-08-24 15:02:38 · answer #3 · answered by chasrmck 6 · 0⤊ 0⤋