English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

4x^2y^5/12x^3y^2z^-3 how do i simplify that. i know its something witht he exponents biut i forget what to do with them. thanks.

2007-08-24 06:26:40 · 4 answers · asked by Anonymous in Science & Mathematics Mathematics

4 answers

4x^2y^5/12x^3y^2z^-3

= y^3z^3 / 3x

Negative exponents in the denominator become positive exponents in the numerator. Negative exponents in the numerator become positive exponents in the denominator.

Subtract exponents when dividing, e.g.

x^2 / x^5 = x^(2-5) = x^(-3) = 1/ x^3

2007-08-24 06:36:23 · answer #1 · answered by MamaMia © 7 · 1 0

the negative exponent tells you z cubed should be moved. In this case it is on the bottom so move it up. All positive exponents stay where they are and all negative ones have to move from where they are. In your last problem you had a negative exponent in the numerator so it moved to the denominator.

Here your fraction becomes:
4x^2y^5 / 12x^3y^2z^-3
the 4 & 12 reduce to 1 and 3
after canceling x's you are left with one x below.
for the y's you are left with y^3 on top
and the z goes to the top as z cubed

(zy)^3 / 3x

2007-08-24 06:41:15 · answer #2 · answered by 037 G 6 · 0 0

move top x's to the bottom, subtracting exponent 3 and 2 also subtracting 12 and 4, then move bottum y to the top subtract exponents. and you can't have a negative exponent on the bottum so you move the z^-3 to the nominator making it z^3 then your left with your answer

y^3z^3/8x

2007-08-24 06:37:52 · answer #3 · answered by sarah 1 · 0 2

Just try dividing or multiplying as needed.

2007-08-24 06:35:59 · answer #4 · answered by muddypuppyuk 5 · 0 1

fedest.com, questions and answers