How would you factor the following?
3xˆ2 - 48???
2007-08-24 06:00:25 · 10 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
3 (x ² - 16)
3 (x - 4) (x + 4)
2007-08-24 06:34:42 · answer #1 · answered by Como 7 · 1⤊ 0⤋
u need to first find the LCF..which is the lowest common factor out of the whole term. 3 can go evenly into 48, and 3 is the lowest common factor. so place the lcf outside the parenthesis! if x had a common then it would also be outside the parenthesis, but since it doesnt it must be included inside the parenthesis:
3(x^2-16) [when u multiply, its still the same as 3x^2-48]
now u have 3(x^2-16) as the factor of 3x^2-48, but notice that u have the difference of squares inside the parenthesis, so u still need to factor and the result is:
3(x-4)(x+4)!! final answer
2007-08-24 07:11:30 · answer #2 · answered by cupcake 3 · 0⤊ 1⤋
3x^2-48
=3(x^2-16)
=3(x+4)(x-4). ANS.
2007-08-24 06:16:51 · answer #3 · answered by Anonymous · 0⤊ 0⤋
3(x^2-16)
3(x-4)(x+4)
The only way to get better with factoring is to do it a million times.
2007-08-24 06:08:14 · answer #4 · answered by magiscoder 3 · 0⤊ 0⤋
divide by 3 (take 3 out) and you'll get:
3xˆ2 - 48 = 3(X^2-16) = 3(x-4)(x+4)
2007-08-24 06:07:59 · answer #5 · answered by supergirl 5 · 0⤊ 0⤋
3x^2 - 48
= 3(x^2 - 16)
= 3 (x^2-4^2)
= 3 (x+4) (x-4)
2007-08-24 06:42:24 · answer #6 · answered by gab BB 6 · 0⤊ 1⤋
3(x^2-16)
=3(x+4)(x-4)
2007-08-24 06:08:12 · answer #7 · answered by de4th 4 · 0⤊ 0⤋
3(x-4)(x+4)
2007-08-24 06:16:03 · answer #8 · answered by ps 3 · 0⤊ 0⤋
3x² - 48 = 0
3(x² - 16) = 0
3(x - 4)(x + 4) = 0
- - - - - - -s-
2007-08-24 06:39:28 · answer #9 · answered by SAMUEL D 7 · 1⤊ 0⤋
hey its preety simple,
Just take three common,
So
3(x^2-16)
therefore 3(x-4)(x+4)
got it????
2007-08-24 06:21:14 · answer #10 · answered by Anonymous · 0⤊ 1⤋