a sheet of aluminum foil has a total area of 1.000ft^2 and a mass of 3.380g. what is the thickness of the foil in millimeters? (density of Al=2.699 g/cm^3).
2007-08-24 05:53:44 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
3.380 grams / 2.699 g/cm^3 = 1.2523 cm^3
1.000 ft^2 = 929.0304 cm^2
Therefore, the thickness is:
1.2523 cm^3 / 929.0304 cm^2 = 1.348 x 10^-3 cm
= 0.001348cm
2007-08-24 06:07:10 · answer #1 · answered by Dave_Stark 7 · 0⤊ 0⤋
When you relate the mass to density, you can determine the volume of the metal. So, g x (cm^3/g) = cm^3. Once you know the value for that, then you convert ft to cm. So next it should be cm x cm x cm = cm^3. You know cm^3 and you know the two sides of sheet (1 square foot) so you just solve for that last cm.
Correction J L, the value is 0.4 mm, not 4.0.
2007-08-24 13:06:50 · answer #2 · answered by chemicalcajun 4 · 1⤊ 0⤋
convert area to cm^2, pretty simple from there, just find what your need to multiply by to change 2.699 to 3.380..............
2007-08-24 13:07:39 · answer #3 · answered by muddypuppyuk 5 · 0⤊ 0⤋
1 ft^2 = 30.48 cm^2
density = weight / volume
2.699 = 3.380 / (30.48x)
30.48x = 3.380 / 2.699
30.48x = 1.252
x = 0.0411 cm therefore x = 4.11mm
the thickness of the foil is 4.11mm
2007-08-24 13:06:30 · answer #4 · answered by J L 2 · 0⤊ 2⤋