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chalcopyrite, the principle ore of Copper (Cu) contains 34.63% Cu by mass. How many grams of Cu can be obtained from 9.83x10^3 kg of the ore?

2007-08-24 05:51:20 · 3 answers · asked by Anonymous in Science & Mathematics Chemistry

3 answers

34.63% of 9.83 x 10^3 (9830) kg = 3404.13kg or 3.404 x 10^3kg


(0.3463 x 9830 = 3404.13)

2007-08-24 05:59:07 · answer #1 · answered by J L 2 · 0 0

Come now, Susan; that's not a chem problem, it's simple math! If something is 34% of the ore, than that means 100 grams of ore gives 34 grams of the something. So, you simply multiply the weight of the ore by the %-age of the something to get the weight of the something you can get from the ore. It's just that simple, right?

2007-08-24 13:24:15 · answer #2 · answered by John R 7 · 0 0

(9.83 x 10^3) / 100 x 34.63%
= 3404.129 kg
= 3404129 g (answer)

2007-08-24 13:03:21 · answer #3 · answered by elish 2 · 0 0

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