Algebra Factoring!!! HELP?

Question

How would you factor the following?

xˆ2 - 4x - 12????

Answer 1

(x+a)(x+b): ab = -12 and a+b = -4 ==> -6, +2, so
(x+2)(x-6)

Answer 2

What two numbers are factors of -12 and add to -4?
The answer is -6 and +2.

So,
x^2 - 4x - 12 = (x - 6)(x + 2)

Use FOIL to verify that this is correct:

x^2 +2x - 6x -12 = x^2 -4x - 12

Answer 3

x^2-4x-12 =
first, get the factors of -12 in order to get -4; and the factors of -12 that would result into -4 are -6 and +2.
hence,
x^2-4x-12 = (x-6)(x+2)
x^2-4x-12 = x^2-6x+2x-12
x^2-4x-12 = x^2-4x-12

Answer 4

Sweetie its (x + 2)(x - 6)

if the problem is x^2 - 4x - 12= 0

the answer would be -2 and 6

Answer 5

x^2-4x-12
=x^2-6x+2x-12
=x(x-6)+2(x-6)
=(x-6)()x+2). ANS.

Answer 6

peace of cake! here is a quick tip!
what 2 numbers multiplied together give u -12 but when u subtract or add them they give u -4?

(x-6)(x+2) this only works for trinomials, sometimes! when u multiply out (x-6)(x+2) it is the same as x^2-4x-12!

Answer 7

x^2-4x-12
=(x-6)(x+2)

x=6 or x =-2

Answer 8

so you have x^2 -4x- 12
so you ask youself : what are factors of 12 that equal -4? it would be -6 and 2. ( -6+2=-4) so
(x-6)(x+2) would be your answer
if you distribute this ( to check yourself ) it would equal
x^2 -4x -12

Answer 9

(x - 6) (x + 2)
Check
x(x + 2) - 6 (x + 2)
x² + 2x - 6x - 12
x² - 4x - 12 (as required)

Answer 10

x² - 4x - 12 = 0

x² - 6x + 2x - 12 = 0

Group factor


(x² - 6x) + (2x - 12) = 0

x(x - 6)+ 2(x - 6) = 0

(x + 2)(x - 6) = 0

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