What is the y-intercept of the line determined by the points (-3, 8) and (-2,-2)?

Question

Show your work and expain if you can

Thanks

Answer 1

m = (- 2 - 8) / (- 2 + 3) = - 10
y - 8 = (-10) (x + 3)
y - 8 = (-10) x - 30
y = (-10) x - 22
y intercept is y = - 22

Answer 2

Suppose the equation of the line in question has the form:
y = mx + b,
where m is the slope, and b is the y-intersect.
Let us find the slope:
m = (y2 - y1)/(x2 - x1)
= (-2 - 8)/(-2 + 3)
= -10
To find the y-intersect, substitute coordinates of either of the two points into
y = -10x + b:
-2 = -10(-2) + b <=>
-2 = 20 + b <=>
b = -22

Answer 3

slope of the line=DY/DX=8+2/-3+2 =10/-1=-10.
The EQ. of the ine is:
y-8=-10(x+3)
y=-10x-22
The Y-intercept of this line is=-22. ANS.

Answer 4

start by finding the slope of the line:
m = (y2-y1)/(x2-x1)
m = (-2-8)/(-2-(-3)) = -10/1=-10
then find the equation of the line using one of the points
y-y1= m*(x-x1)
y-8 = -10*(x+3)

the y-intercept is when the line croses the y-axis, so x=0
y-8 = -10*(3)
y = -30 +8
y=-22
so the y-intercept is (0,-22)

Answer 5

You first find the slope using the formula:

m=(8+2)/(-3+2)=-10

Then you use the point-slope formula to get the intercept.

y-y1=m(x-x1) where (x1, y1) can be (-2, -2) because it is easier to work with.

y+2=-10 (x+2)
y+2=-10x-20
y=-10x-22

y-intercept is -22.