Given Quadrilateral ABCD and the points A(-2, 6), B(4, 6), C(4, -3) and D(-2, -3). Use the distance formula to find the lengths of each side. Give the most specific name for this polygon. Show all your work.
2007-08-24 04:49:40 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
AB² = 6² + 0²
AB = 6
AB = CD
CD² = (- 6)² + 0²
CD = 6
BC² = 0² + (- 9)²
BC = 9
DA² = 0² (- 9)²
DA = 9
BC = DA
Opposite sides are equal
mAB = (6 - 6) / (4 + 2) = 0 (AB horizontal)
mBC is undefined (BC is vertical)
mCD = 0 (CD is horizontal)
mAD (AD is vertical)
Opposite sides are equal and all angles are 90°
ABCD is a rectangle.
2007-08-24 06:31:59 · answer #1 · answered by Como 7 · 2⤊ 0⤋
the distance formula is d = sq. rt( (x2-x1)^2 + (y2-y1)^2 )
side AB is sq. rt (-2-4)^2 + (6-6)^2) which results in 6.
Plug the coordinates of sides BC, CD, and DA.
Side BC = 9
side CD = 6
side DA = 9
The shape is a rectangle.
2007-08-24 12:17:10 · answer #2 · answered by dawn007 2 · 0⤊ 0⤋
Given the two points (x1, y1) and (x2, y2), the distance between these points is given by the formula
2007-08-24 12:04:50 · answer #3 · answered by live for today 4 · 0⤊ 0⤋
AB = CD = 6
AD = BC = 9
This is a rectangle.
2007-08-24 12:08:47 · answer #4 · answered by FIESTA 3 · 0⤊ 0⤋