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An object is propelled vertically upward with an initial velocity of 20 meters per second. The distance s (in meters) of the object from the ground after t seconds is s = -4.9t^2 + 20t.

(1) When will the object be 15 meters above the ground?

(2) When will the object strike the ground?

2007-08-24 01:17:59 · 2 answers · asked by journey 1 in Science & Mathematics Physics

2 answers

You have two quadratic equations:
For (1), s = 15 = -4.9t^2 + 20t, so -4.9t^2 + 20t -15 = 0
For (2), s = 0 = -4.9t^2 + 20t, so -4.9t^2 + 20t = 0
Use the standard method for solving these.

2007-08-24 03:48:51 · answer #1 · answered by kirchwey 7 · 0 0

42

2007-08-24 01:25:52 · answer #2 · answered by weiner42 1 · 0 0

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