write an equation in slope-intercept form for the line that has indicated slope: m=3, (-4, 9)?

Answer 1

y - 9 = 3 (x + 4)
y - 9 = 3x + 12
y = 3x + 21

Answer 2

OK let's just start with point-slope form and manipulate it into slope-intercept form. For a line with point (x1, y1), slope of m, and y-intercept of b, we have the following equations for a line:

point-slope form: y - y1 = m(x - x1)

slope-intercept form: y = mx + b

So, let's just plug in the point (x1, y1) = (-4, 9) and slope of m = -2/3 into the first equation:

y - 9 = 3(x - (-4))
==> subtracting a negative is the same as adding a positive
y - 9 = 3(x + 4)
==> distribute the 3
y - 9 = 3x + 12
==> add 9 to both sides
y = 3x + 21

So, your final answer is: y = 3x + 21.

Answer 3

When you have the slope and a point in the curve you use the expression:

y+y1=m(x-x1),

so we substitute the values you have:

y+9=3(x-(-4)) => y= 3x+12-9 => y=3x+3

which is the equation in the form slope-intercept you desire, with slope m=3 and interception with the y-axis at (0,3).

Hope this help you.

Answer 4

M=3, points (x,y), (-4,9)
M=(y-9)/(x- -4)
3= (y-9) / (x+4)
3*(x+4)=(y-9)
3x+12=y-9
3x+21=y
therefore the equation of the line is
y=3x+21