2007-08-23 18:45:28 · 6 answers · asked by ChArLeNe N 1 in Science & Mathematics ➔ Mathematics
y + 5 = (-2/3)(x - 6)
3y + 15 = - 2x + 12
3y = - 2x - 3
y = (- 2/3) x - 1
2007-08-23 20:22:21 · answer #1 · answered by Como 7 · 2⤊ 0⤋
Slope intercept form is y=mx+b. Unfortunately, we aren't given the intercept, so we have to use the point-slope form: y-y1 = m(x-x1), and manipulate it algebraically
y - -5 = (-2/3)(x-6)
y + 5 = (-2/3)(x) - (-2/3)(6)
y + 5 = -2x/3 + 12/3
y + 5 = -2x/3 + 4
y = -2x/3 - 1
y = (-2/3)x - 1.
2007-08-24 01:55:21 · answer #2 · answered by hogan.enterprises 5 · 0⤊ 0⤋
Equation to the line through (6, --5) and slope m = --2/3 is
y -- (--5) = (--2/3)(x --6)
y + 5 = --2x/3 + 4
3y + 15 = --2x + 12
Or y = (--2/3)x -- 1 ...............(slope form)
And x/3 + y/2 = --1/2 ........(intercept form)
2007-08-24 01:59:11 · answer #3 · answered by sv 7 · 0⤊ 0⤋
slope intercept form
y = mx + b
y - y1 = m(x-x1)
y -(-5) = -2/3 (x - 6)
y + 5 = - 2x/3 + 1
[y + 4 = -2x/3]3
3y + 12 = -2x
3y = - 2x - 12 --- equation of the line
simplifying:
y = -2x/3 - 4 ---eq of the line in the SI form : y = mx + b
2007-08-24 01:53:40 · answer #4 · answered by toffer 3 · 1⤊ 0⤋
y+5=-2/3(x-6)
2007-08-24 01:51:31 · answer #5 · answered by Anonymous · 0⤊ 0⤋
slope intercept form(here c=-5)
y=mx+c
y=(-2/3)x-5
y=-2x-15/3
2007-08-24 01:57:15 · answer #6 · answered by snehalu 3 · 1⤊ 0⤋