How many liters of 1.5 M KF should be added to a resovoir w/a diameter of 100m&a depth of 20m to give1.2ppm F-

Answer 1

So the volume of the resovoir is 3.14159*50*50*20*1000L = 1.57E8 (L). With such diluted solution as 1.2ppm F-, we can let the density of the solution to be 1kg/L, so the weight of the total solution is 1.57E8(kg). 1.2ppm F- by weight in 1.57E8(kg) is 188kg. The atomic weight of F is 19, hence 1L of 1.5M KF contains 28.5g of F-. 188kg/(28.5g/L) = 6.6E3 (L). So the answer is 6.6E3 Liters by weight.