Find the width of a rectangle if the length is 12 cm and the perimeter is 40 cm.
5 cm
8 cm
16 cm
28 cm
2007-08-23 14:28:35 · 8 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Let width = W
2(12 + W) = 40
12 + W = 20
W = 8 cm
2007-08-27 08:00:10 · answer #1 · answered by Como 7 · 0⤊ 0⤋
12+12=24 and 40-24=16 so the other two sides have to be the same length. so 16 divided by two is 8. so the answer is 8cm. Sometimes drawing a picture will help
2007-08-23 14:34:35 · answer #2 · answered by x23xlaurenx32x 2 · 0⤊ 0⤋
okay here we go.
the perimeter = 40 cm
the length = 12 cm
remember, a rectangle has 2 pairs of parallel sides...
since the perimter is length + length + width + width, you use the equation...
l + l + w + w = p
12 + 12 + x + x = 40
24 + x = 40
so the width is 40 - 24, which is 16. hope i helped!
2007-08-23 14:41:09 · answer #3 · answered by Anonymous · 0⤊ 0⤋
8 cm
2007-08-23 14:40:16 · answer #4 · answered by Kantilal Mane 1 · 0⤊ 0⤋
8 cm
2007-08-23 14:35:36 · answer #5 · answered by Rob M 6 · 0⤊ 0⤋
Perimeter is P= 2L + 2w (because you add 2 lengths and 2 widths)....
2L + 2w = 40
2(12) + 2w = 40
24 + 2w = 40
2w = 16
w = 8
2007-08-23 14:41:13 · answer #6 · answered by Anonymous · 0⤊ 0⤋
8 cm
perimeter - length X 2 (there are 2 of them) 40cm - 2(12cm) = 16cm
divide the answer by 2 (there are also 2 widths) 16cm/2= 8cm
2007-08-23 14:36:19 · answer #7 · answered by MKC 4 · 0⤊ 0⤋
well you could do.2 sides of 12 and 2 sides of 8..
2007-08-23 14:35:15 · answer #8 · answered by Heather S 2 · 0⤊ 0⤋