how to graph Y= cosX+[cosX] the [ ] means absolute balue here.?

Question

thanks

Answer 1

Y = 0, on [pi/2, 3pi/2]
Y = 2cosX, on [0, pi/2] and [3pi/2, 2pi]
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Ideas: Since Y is a periodic function, after you graph the function on [0, 2pi], you can copy it to [2pi, 4pi]...etc.

Answer 2

You know the graph of y=cosX correct?

By taking an absolute value, while y=cosx is positive, it will act like y=2cosX. While y=cosx is negative, it will completely cancel out the cosx. That means you get y=2cosX for an interval where cosX is positive, y=0 when cosX is negative.

Answer 3

double the amplitude when cos x has positive value and a straight line on axis-x (y=0) when not