x^2+4x-32=0
2007-08-23 11:47:24 · 2 answers · asked by flangel80190 2 in Education & Reference ➔ Homework Help
If I remember correctly...
take half of the middle number= 2 and square that =4
then add 4 to the end and subtract it from the last digit
So x^2 +4x+4 (-32-4)
then I think you subtract the last digit so it is on the other side
x^2 +4x+4= 36
the point of this is so that it factors squarely (x+2)^2=36 and can be solved easily
Not my favorite method
2007-08-23 12:01:07 · answer #1 · answered by The Great and Powerful Jen 3 · 0⤊ 0⤋
x² + 4x - 32 = 0
We will change the constant term to make the left side a square term by adding 36 to both sides of the equation.
x² + 4x - 32 + 36 = 36
x² + 4x +4 = 36
(x + 2)² = 36
x + 2 = ±6
x = 4, x= -8
.
2007-08-23 19:16:42 · answer #2 · answered by Robert L 7 · 0⤊ 0⤋