Find the roots using the quadratic formula??

Question

A) 2x^2+x-12=0


B) 4x^2-2x=7



Please show all the steps so i understand for other questions

Answer 1

A) 2x^2+x-12=0
or 2x^2+x+(-12)=0
or x={-b+-sq rt(b^2-4ac)}/2a,for the equation
ax^2+bx+c=0
so x={-1+-sq rt(1-4*2*(-12)}/4
or x={-1+-sq rt(1+96)}/4
or x={-1+-sq rt(97)}/4 ans

Answer 2

2x^2+x-12=0

The Quadratic Formula
x = {-(b) ±√[(b)² - 4(a)(c)]}/[2(a)]
Substituting
x = {-(1) ±√[(1)² - 4(2)(-12)]}/[2(2)]
x = {-1 ±√[1 - -96]}/4
x = {-1 ±√[97]}/4
If you need a numeric answer, you can do the calculator work at least as well as I can.

Ok, not very pretty... but sometimes the quadratic formula does that.


4x^2-2x=7 Ok a little twist here... add -7 to both sides...
4x^2-2x-7=0
Substituting
x = {-(-2) ±√[(-2)² - 4(4)(-7)]}/[2(4)]
x = {2 ±√[4 - -112]}/8
x = {2 ±√[116]}/8
Altough this is little cleaner, but you can doth arithmetic/calculator work..

Answer 3

Quadratic Equation and Formula
ax² + bx + c = 0
x = (-b ± √(b² - 4ac))/2a


a)
2x² + x - 12 = 0

x = (-b ± √(b² - 4ac))/2a

x = (-1 ± √(1 + 96))/4

x = (-1 ± √(97))/4

b)
4x² - 2x - 7 = 0

x = (-b ± √(b² - 4ac))/2a

x = (2 ± √(4 + 112))/8

x = (1 ± √(29))/4
.

Answer 4

1. a=2, b=3, c=-12

2. a=4, b=-2, c=-7

Just plug and chug.