Acidity percentage?

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Just part of a Chem. question.

If the molarity of acetic acid is 0.01735 moles/liter, what is the percent acidity of 10.23 mL vinegar?

P.s.- Acetic acid is 60 grams per mol.

2007-08-23 11:06:38 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry

2 answers

0.01735 moles/L x 60 g/mole = 1.041 g/L
acidity = 1.04% (m/v) acetic acid.
(10.23 mL was thrown in to see if you understood what you were doing).

2007-08-23 11:44:38 · answer #1 · answered by skipper 7 · 0⤊ 1⤋

1/60 x 10.23/1000 x 0.01735 x 100

2007-08-23 11:17:07 · answer #2 · answered by Gervald F 7 · 0⤊ 0⤋