moe owns 3/5 of a company and roger owns 1/8 of it...then how much is owned by frank?
2007-08-23 09:03:17 · 3 answers · asked by Anonymous in Education & Reference ➔ Homework Help
Together Moe & Roger own 3/5 + 1/8 = 29/40.
Subtract the 29/40 from One (the total of "it") and you get 11/40. That's how much Frank owns: 11/40.
2007-08-23 09:50:48 · answer #1 · answered by Marley K 7 · 0⤊ 0⤋
On the asssumoption that Frank owns the remainder then you deduct the portions owned by Moe and Roger. First you have to convert them to a common deniominator so
This would be 40 (5 x 8)
So Moe owns 24/40ths (3 x 8)
and Roger owns 5/40 (1 x 8)
Together they have 24/40 + 5/40 = 29/40
40/40 (One whole) - 29/40 leaves 11/40
So Frank owns 11/40ths
2007-08-23 16:31:16 · answer #2 · answered by quatt47 7 · 0⤊ 0⤋
i think its 11/40 because u have 2 do the same bottom # then multiplie that # 2 the top #'s then subractthta # from the bottom
2007-08-23 16:11:34 · answer #3 · answered by BookWorm 2 · 0⤊ 0⤋