Water has a mass per mole of 18.0g/mol, and each water molecule (H2O) has 10 electrons. a) How many electrons are their in one liter (1.00 x 10 to the negative third mto the third) of water? b) What is the net charge of all these electrons?
2007-08-23 08:42:29 · 3 answers · asked by Diane S 1 in Science & Mathematics ➔ Physics
One mole of any molecule contains
6.022x10^23 molecules. So 18.0 grams of water would have
6.022x10^24 electrons. One liter of water has a mass of
1000 grams.
(1000/18.0) x 6.022x10^24 is the number of electrons in one liter of water.
2007-08-23 09:20:57 · answer #1 · answered by Anonymous · 0⤊ 0⤋
a) Scot got it right. Numerically the answer is 3.344E26 electrons per L
b) Multiply a) by 1.6019E-19 coul/electron to get the final answer of 5.357E7 coulombs/L
2007-08-23 16:31:31 · answer #2 · answered by Steve 7 · 1⤊ 0⤋
electrons in 1L
= 1L(1000g/L)(18mol/g)(6.022* 10^23 atoms/mol)(10e/atom)
=1.08396 Ã 10^29e
1.08*10^29e(1.6*10^-19coulomb/e) = 1.7366952 Ã 10^10 coulombs
2007-08-23 16:17:14 · answer #3 · answered by supastremph 6 · 0⤊ 0⤋