-4^0 – 8^0
2007-08-23 07:45:31 · 10 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Any number to the zero power is one, except for zero.
There you go.
2007-08-23 07:50:03 · answer #1 · answered by Brian L 7 · 0⤊ 0⤋
An equation requires an = sign.
(- 4)^0 - 8^0
= 1 - 1
= 0
2007-08-27 13:48:52 · answer #2 · answered by Como 7 · 0⤊ 0⤋
= - 4^0 - 8^0
= 0 - 0
= 0
Answer: 0
2007-08-27 09:39:32 · answer #3 · answered by Jun Agruda 7 · 3⤊ 0⤋
anything to the 0 power is 1 so this is 1-1 or 0
note though that -(4^0) is not the same as (-4)^0. I am assuming the latter.
2007-08-23 14:51:12 · answer #4 · answered by chasrmck 6 · 1⤊ 1⤋
It equals 0
2007-08-23 14:50:00 · answer #5 · answered by peteryoung144 6 · 0⤊ 0⤋
An "equation" has an "equal" sign (=) in it. That is not an equation.
As for the result of that "difference", any finite number elevated to 0 yields 1, so: -1-1 gives -2
2007-08-23 14:54:52 · answer #6 · answered by franz_himself 3 · 1⤊ 0⤋
Rule: Any number raised to the zero power is 1.
So: 1-1=0
2007-08-23 14:51:44 · answer #7 · answered by Anonymous · 0⤊ 0⤋
-4^0 is -1 and 8^0 is 1
so the answer is -2.
any doubts with y -4^0 is -1 ???
check this http://mathforum.org/library/drmath/view/55721.html
2007-08-23 14:58:15 · answer #8 · answered by Serenity 2 · 0⤊ 0⤋
-4^0 – 8^0 = -2
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Attention: -4^0 â (-4)^0
2007-08-23 14:49:58 · answer #9 · answered by sahsjing 7 · 0⤊ 0⤋
0
any number raised to the zero power is 1
Therefore 1-1=0
2007-08-23 14:51:03 · answer #10 · answered by rocket_scientist_guy 1 · 0⤊ 0⤋