What is the volume of a pyramid of height 10cm wen the baseis an equilateral triangle wit sides of length 12cm

Answer 1

Area of the base = Area of the equilateral triangle
= sqrt3 (side)^2 / 4
= 62.352 cm^2

Volume of a pyramid = 1/3 * Area of base * Height
= 62.352 * 10 /3
= 207.84 cm^3

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Answer 2

Area of base = (1/2) x 12 x 12 sin 60° cm²
Area of base = 72 sin 60° cm²
Volume = (1/3) x 72 sin 60° x 10 cm ³
Volume = (1/3) x 720 x √3 / 2 cm ³
V = 120 √3 cm ³
V = 207.8 cm ³ (to 1 decimal place)

Answer 3

volume of a pyramid=1/3(area of base)* H

area of the base(triangle)=1/2*base*H
=1/2*(12)*sq rt(12^2-6^2)
=6*sq rt (108)
= 6*6 sq rt(3)
=36 sq rt(3)
so the volume of pyramid=1/3{36sq rt(3)}*10 cu cm
=120 sq rt(3) cu cm
=120*1.732(app) cu cm
=207.84 cu cm (app)