2007-08-23 07:11:37 · 7 answers · asked by sure222 5 in Science & Mathematics ➔ Mathematics
and how do you solve it
2007-08-23 07:13:55 · update #1
(x^2)(sqrt Y) or (x^2)(Y^1/2)
2007-08-23 07:19:50 · answer #1 · answered by e-man 3 · 0⤊ 0⤋
when you see a negative in the exponent, you can always 'get rid of it' by transfering the variable with the negative exponent to the numerator or denominator:
x^2/y^-(1/2) = x^2y^(1/2)
You would need another equation to solve for x and y.
2007-08-23 14:18:20 · answer #2 · answered by miggitymaggz 5 · 0⤊ 0⤋
x^2 / Y^2
2007-08-23 14:14:42 · answer #3 · answered by tonysae 2 · 0⤊ 3⤋
x^2 times root y (btw this can also be writen as x^2y^(1/2)
but as to how to solve it im sorry but i cant help you
2007-08-23 14:17:50 · answer #4 · answered by Adam W 1 · 0⤊ 0⤋
( x ² ) y^(1/2) is the answer.
2007-08-27 12:02:14 · answer #5 · answered by Como 7 · 0⤊ 0⤋
x^2/y^(-1/2) = x^2y^(1/2)
2007-08-23 14:15:35 · answer #6 · answered by sahsjing 7 · 1⤊ 0⤋
x^2 * y1/2
Like it was said, but not enough info to solve it
2007-08-23 14:20:18 · answer #7 · answered by BUddy1017 2 · 0⤊ 0⤋