algebra 2 help?

Question

What are the equations of the asymptotes for the hyperbola (y+3)^2 – (x+2)^2/9 = 1?

A y+3 = ± (x+2)/3
B y+3 = ± (x+2)/9
C y+3 = ± 3(x+2)
D y+3 = ± (x+2)/3 + 1
E y+3 = ± (x+2)/9 + 1
F None of the above

Answer 1

When you have y²/b² - x²/a² = 1, slope of asymptotes is ±b/a, which here is 1/3. Here the center is translated to (-2,-3), so the equations are y+3 = ±(x+2)/3, answer A.