please help me solve this conjunction -2<= a + 3 < 8?

4 ⤊

please help me solve this conjunction -2<= a + 3 < 8?

-2 <= a + 3 < 8

2007-08-23 06:34:35 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

3 answers

-2 <= a + 3 < 8

Subtract 3 from all three members.

-5 <= a < 5

So is greater than or equal to -5 and a is less than 5.

2007-08-23 06:38:12 · answer #1 · answered by DavidK93 7 · 0⤊ 0⤋

- 2 <= a + 3 < 8
- 2 - 3 <= a < 8 - 3
- 5 <= a < 5

2007-08-27 01:33:10 · answer #2 · answered by Jun Agruda 7 · 3⤊ 0⤋

Subtract 3 from each part to get:

-5<= a < 5

That's it. You can graph this on the number line with a closed circle (shaded) at -5 and open circle at +5, connecting the two circles. Or, you can write it in interval notation: [-5,5).

2007-08-23 06:39:43 · answer #3 · answered by Marley K 7 · 1⤊ 0⤋