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Find the eccentricity of the following:
x^2/16 + y^2/25 = 1

A SQRT(3/5)
B 3/4
C 4/5
D 3/5
E 5/3
F SQRT(4/5)

2007-08-23 06:30:32 · 3 answers · asked by Anonymous in Science & Mathematics Mathematics

3 answers

if you think of "a" as the semi-major length, here it's 5. e = c/a, and c² = a²-b² = 25-16 = 9, so c = 3. that makes eccentricity 3/5, D.

2007-08-23 06:35:29 · answer #1 · answered by Philo 7 · 0 1

Since y^2 has a larger divisor than x^2, the semi-major axis is parallel to the y-axis. The eccentricity is sqrt(1 - 16/25) = sqrt(9/25) = 3/5, choice D.

2007-08-23 13:36:13 · answer #2 · answered by DavidK93 7 · 0 1

Work out your own homework or you are cheating yourself........

2007-08-23 13:33:39 · answer #3 · answered by muddypuppyuk 5 · 0 0

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