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2007-08-23 04:51:09 · 2 answers · asked by Anonymous in Science & Mathematics Mathematics

2 answers

=[2xa/2x*(2x+h) - (2xa + ah)/2x(2x+h)]*1/h
= -a/(2x)*(2x+h)

Now if they ask what the solution is as h approaches 0, the answer is
= -a/4x^2

2007-08-23 05:18:40 · answer #1 · answered by sharky.mark 4 · 0 0

((a/2x+h) - (a/2x)) * 1/h
= h/h = 1

2007-08-23 11:58:31 · answer #2 · answered by ironduke8159 7 · 0 0

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