0=80t-16t²
t=80/16 or 5 seconds or at 0 seconds
2007-08-23 04:57:07
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answer #1
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answered by chasrmck 6
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Plug 0 in for H. You cna factor a t out of 80t-16t^2, giving you 0=t(80-16t) By the zero product property, we know that either t=0 or 80-16t=0. We know that the first answer, t=0, is when the ball is thrown. Solving the second equation gives us t=5. So, the ball will land after 5 seconds, minutes, hours or whatever the unit of time is.
2007-08-23 05:15:02
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answer #2
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answered by gannonbp 1
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h=80t -16t^2
the ball is on the ground when h = 0, so:
0 = 80t -16t^2
= t(80 - 16t)
= t(80/16 - t)
= t(5 - t)
the ball will be on the ground at t = 0 (when it was thrown) and t = 5 (when it lands).
so there's your answer:
the ball will land at t = 5
2007-08-23 04:59:37
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answer #3
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answered by BrightEyes 5
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this equation is in the form of newon's second law of motion which is of the form s=ut+1/2 at^2
where u=80
a=-32
the ball will be at the top when v=0
thus, the time taken for the ball to reach top will be determined by newton's first law of motion
v=u+at
0=80-32*t
t=80/32 = 2.5 so the time taken to reach the top is 2.5, the same time would be taken to fall back will be the same
so the time when the ball falls back would be 2.5 * 2= 5
2007-08-23 05:02:43
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answer #4
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answered by shubham_nath 3
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Will land when h = 0
16t (5 - t) = 0
t = 0 , t = 5.
Ball will land after 5 seconds (presumably)
2007-08-27 04:51:22
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answer #5
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answered by Como 7
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wen t=0 ot t=5
but at t=0 it can't land
so it'll land wen t=5
2007-08-23 04:58:42
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answer #6
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answered by Anonymous
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