Which number is divisible by all numbers from 1 to 9?

Answer 1

You are asking what is the smallest of such numbers, I guess
Thats LCM of (1,2,3,4,5,6,7,8,9)

1 = 1
2 = 2 x 1
3 = 3 x 1
4 = 2 x 2
5 = 5 x 1
6 = 3 x 2
7 = 7 x 1
8 = 2 x 2 x 2
9 = 3 x 3

LCM = 3^2 x 2^3 x 5 x 7 = 2520

Answer 2

1

Answer 3

Short answer: 2520

How to do it:
Start by multiplying with the largest number, and take out numbers that are already included (for example, if you use 9, you don't need to multiply by 3, because 9 already is divisible.

9 (don't need 3)
8 (dont need 2 or 4)
7
6 (dont need 2 or 3)
5

So you just need to multiply 9*8*7*6*5 = 15120

Now divide out the numbers you didn't need more than once, because these are factored in twice (for example, both 9 and 6 would make it divisible by 3, so you don't need one of these 3s)

15120 / 3 / 2
= 2520

Answer 4

2520. You only have to concern yourself with the interactions between the prime numbers. 2,3,5,7

2*3*5*7 = 210. Then 210*3*4 to ensure that 8 and 9 are divisible. 210*3*4 = 2520.

Answer 5

9 * 8 * 7 * 5 = 2520.

We don't need to include 6, 4, 3 and 2 because these are covered by 9 and 8.

Answer 6

2x2x2x3x3x5x7(multiply them together)Try it and divide by each of the numbers 1-9. See if they all come out even.

2=2
3=3
2x2=4
5=5
2x3=6
7=7
2x2x2=8
3x3=9

Answer 7

The obvious answer is 9!

The smallest possible is 9*8*7*5 = 2520

Answer 8

360 is divisible by all the numbers you listed EXCEPT 7.
360 x 7 is therefore the number you seek. 2520

Answer 9

1
it's just simple

Answer 10

one (1) ?