I have 2787 worms per 1 milliliter of 'slurry'. (yes, worms, little tiny ones) I need 50 worms per 200 microliters. Will someone else do the dilution to so I know I'm right? Best anwer to the first correct and understandable!
2007-08-23 03:41:29 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
It is an actual case. (and that's not an answer, that's another question!) I'm working with the barberpole worm. I got 18 and Doc got 17.9, so I'm good. Thanks!
2007-08-23 04:11:13 · update #1
Volume in mL that contains 50 worms = 50 x 1 / 2787 =
= 0.0179 mL
1 microliter = 10^-6 L= 10^-3 mL
0.0179 mL = 17.9 microliter
In 17.9 microliter there are 50 worms
so we have to take 17.9 microliters and we have to add enought water to reach 200 microliter
2007-08-23 04:04:59 · answer #1 · answered by Dr.A 7 · 0⤊ 0⤋
First, you need to convert milliliters to microliters or vice versa. (microliters to milliliters) The units need to match.
It then becomes a math problem. Set up the equation and solve.
2007-08-23 10:51:04 · answer #2 · answered by Unsub29 7 · 0⤊ 0⤋
Is this a mathematical problem or an actual case ?
2007-08-23 11:03:04 · answer #3 · answered by ag_iitkgp 7 · 0⤊ 1⤋