calulate the heat combustion of propane in KJ/mole.?

Question

C3H8(g) + 5O2(g) ----> 3CO2(g) + 4H2O(g)
TABLE
Compound standard enthalpy of formation (KJ/mole)
C3H8(g) -103.85
O2(g) 0
CO2(g) -393.51
H2O(g) -241.82

Answer 1

do this que with mole concept

Answer 2

(3 x the value for CO2) + (4 x the value for water) - (1 x the value for propane).

Now you can work it out!