A five digit number is formed using digits 1,3,5,7 & 9 without repeating any are of these.?

Question

A five digit number is formed using digits 1,3,5,7 & 9 without repeating any are of these. What is the sum of all such possible numbers?

Answer 1

The possible ways are simply 5!. ©

5! = 120

For each decimal place, 24 of these are of the same digit.

Thus for a decimal place the total value is 24 (1 + 3 + 5 + 7 + 9)
= 600
To get the total value of all these numbers multiply the first result by 11111.

Thus the total value is 6,666,600.

Answer 2

The possible five diget numbers formed is
5x4x3x2x1=120 numbers

The number of times each diget exist in a column
120/5 = 24 x each diget in a column

each column total is
24x(9+7+5+3+1) = 600

This give the sum total as 6666600

Answer 3

The number of possible combinations is 5! = 120. Each digit will be in each position an equal number of times, namely
5!/5 = 24 times.

So the sum of the digits in the one's place is

24(1+3+5+7+9) = 24*25 = 600

This will be the sum of the digits in each place (one's, ten's, etc.). So the total sum is:

600*11,111 = 6,666,600

Answer 4

i'd guess 6666600. am i right?

thanks for the thumbs down, jackass. I was the first one with the right answer, btw. did it in my head. took me 3 minutes, because i am VERY rusty. i had to relearn basically everything.

i think the guy above me copied his from the guy below