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If z1 = 1 - 5i and z2 = 3 + 4i

z1 / lz2l

i.e. What is z1 divided by (the absolute value of z2)??

2007-08-21 21:35:42 · 2 answers · asked by jeska102 1 in Science & Mathematics Mathematics

2 answers

actually, its not an absolute value :D. its called modulus. to get the modulus of say a complex number a+bi,
|a+bi|=sqrt(a^2 + b^2). Doing so for z2, |z2|=sqrt(9+16) = sqrt of 25 which is simply 5. hence, we can now divide z1 by 5:
this yields to:
z1/5 = (1-5i)/5 = 1/5 - i. there you go! i hope you understand :D:D:D

2007-08-22 00:40:07 · answer #1 · answered by mikael 3 · 0 0

|z2| = √(3^2 + 4^2) = 5.
So z1 / |z2| = 1/5 - i.

2007-08-22 04:41:30 · answer #2 · answered by Scarlet Manuka 7 · 1 1

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