English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

6 answers

0 if notin changes...

2007-08-21 21:21:26 · answer #1 · answered by Anonymous · 0 0

The pilot will try for constant deceleration:
240 = 20v - 200a
v = 20a
20v - 10v = 240
v = 24 fps downward

Note that assuming a constant speed of descent requires the helicopter to slam into the ground at 12 fps, which is hard on both the helicopter and the passengers.

2007-08-22 04:56:24 · answer #2 · answered by Helmut 7 · 0 0

velocity=speed = 240/20 =12 feet/per sec

2007-08-22 04:33:33 · answer #3 · answered by Leprechaun 6 · 0 0

velocity=displacement covered/ time taken
=240/20
=12 feet per second
speed = distance covered/ time
if the helicopter covered a straight line distance then speed and velocity are the same

2007-08-22 04:33:23 · answer #4 · answered by shubham_nath 3 · 0 0

Distance = 240 ft
Time = 20 sec
V = distance / time
Velocity required = 240 /20
Velocity required = 12ft/sec

Ignoring, friction

Assuming a constant decent and a rather rough landing i.e not allowing for any hovering

2007-08-22 07:01:39 · answer #5 · answered by Ferra13 2 · 0 0

20 feet per second

2007-08-22 04:20:47 · answer #6 · answered by Avishay Zeta 2 · 0 1

fedest.com, questions and answers