ESTIMATE: The angular acceleration a frisbee undergoes while someone is throwing it (i.e, from rest to the ins

Question

ESTIMATE: The angular acceleration a frisbee undergoes while someone is throwing it (i.e, from rest to the instant it leaves their hand).

Answer 1

The angular acceleration of a Frisbee depends on the angular speed (Greek letter omega) it attains when it leaves the thrower's hand, and the length of time the acceleration is applied by the thrower's hand. If you have estimates on these two quantities you can do the calculation yourself. Just be sure to keep track of whether you are using revolutions per second or radians per second.
For example:
Lets say you estimate the angular speed as 60 revolutions per second.
60 revolutions per second = 60(2pi) = 376.99 radians per second.
Lets say you further estimate the Frisbee undergoes acceleration for one tenth of a second(0.1 seconds). Here's your calculation:
Angular acceleration = angular velocity / time
Angular acceleration = 376.99 / 0.1 = 3769.9 radians per second squared

Angular acceleration is the rate of change of angular velocity over time. In SI units, it is measured in radians per second squared (rad/s2), and is usually denoted by the Greek letter alpha. There are 2pi radians in one complete revolution.